5(2^x)=7^2-x

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Solution for 5(2^x)=7^2-x equation: 



5(2^x)=7^2-x

We move all terms to the left:

5(2^x)-(7^2-x)=0

We get rid of parentheses

52^x+x-7^2=0

We add all the numbers together, and all the variables

x+52^x-49=0

We move all terms containing x to the left, all other terms to the right

x+52^x=49

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